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Be sure to rearrange the records whenever a new record is added or an existing record is deleted, so that the records are always maintained in alphabetical order. 9.64 Repeat Problem 9.63 utilizing a random access data file. Compare with the sequential data file version from a standpoint of programming ease and execution speed. Extend the BINGO program written for Problem 8.60 so that each letter-number combination is stored in a data file as it is drawn, in addition to displaying the letter-number combination. Include the following features. (a) Display each letter-number combination as it is drawn. (b) Display the entire game history (i.e., display the contents of the data file). Remember to initialize (erase) the data file at the beginning of each new game.

else tout CC "NG"; The braces are needed here to override the else matching rule. This else is intended to match the first i f. The second statement should be written if (n > 2) if (n c 6) tout << "OK"; else tout CC "NG"; Here the braces are not needed because the el se is intended to be matched with the second i f.

15.7 Constructing a parallelogram Construct a parallelogram given the lengths of two adjacent sides a and b and of a diagonal d (Fig. 15-21).

Write and run a program that reads the user s age and then prints You are a child. if the age < 18, You are an adult. if 18 I age < 65, and You are a senior citizen. if age 2 65.

Fig. 15-21

Here weusedthe else if construct because the three outcomes depend upon age being in one of three disjoint intervals: main0 int age; tout << "Enter your age: "; tin >> age; if (age < 18) tout CC "You are a child.\n"; else if (age c 65) tout CC "You are an adult.\n"; else tout CC "you are a senior citizen.\&';

Three vertices of the parallelogram are obtained by constructing ^ABD by construction 7. The fourth vertex, C, is obtained by constructing ^BCD upon diagonal BD by construction 7. Vertex C may also be obtained by constructing BC AD and DC AB.

If control reaches the second condition ( age c 6 5 ) , then the first condition must be false so in fact 18 < age < 65. Similarly, if control reaches the second el se, then both conditions must be false so in factage 2 65. 2.17

Given: Circle O and point P on the circle (Fig. 15-22) To construct: A tangent to circle O at P 4 4 4 Construction: Draw radius OP and extend it outside the circle. Construct AB ' OP at P. AB is the required tangent. (A line perpendicular to a radius at its outer extremity is a tangent to the circle.)

Write and run a program that reads two integers and then uses the conditional expression oper-

Fig. 15-22

ator to print either multiple or not according to whether one of the integers is a multiple of the other.

(a) (b)

An integer m is a multiple of an integer n if the remainder from the integer division of m by n is 0. So the compound condition m % n == 0 I I n % m == 0 tests whether either is a multiple of the other: main0 1 int m, n; tin >> m >> n; tout << (m % n == 0 II n % m == 0 'multiple" :

Fig. 15-23

"not") << endl;

Given: Circle O and point P outside the circle (Fig. 15-23) To construct: A tangent to circle O from P Construction: Draw OP, and make OP the diameter of a new circle Q. Connect P to A and B, the intersections of circles O and Q. Then PA and PB are tangents. (jOAP and jOBP are right angles, since angles inscribed in semicircles are right angles.)

The value of the conditional expression will be either I mu1 t ipl e I o r I not I , according to whether the compound condition is true. So sending the complete conditional expression to the output stream produces the desired result.

Given: ^ABC (Fig. 15-24) To construct: The circumscribed circle of ^ABC Construction: Construct the perpendicular bisectors of two sides of the triangle. Their intersection is the center of the required circle, and the distance to any vertex is the radius. (Any point on the perpendicular bisector of a segment is equidistant from the ends of the segment.)